O total de átomos contidos em 49g de H2SO4.

H=2x1g= 2
S=1x32g= 32
0=4x16g= 64
Total= 98g
Agora vamos calcular quantos mols temos em 49g de H2SO4.
98g........1mol
49g............x
98x=49.1
x=49/98=0,5mol
Convertendo para átomos:
1mol.....6.10^23 átomos
0,5mol..........b
b=0,5.6.10^23= 3.10^23 átomos.
Portanto, em 49g de H2SO4 contém 3.10^23 átomos.
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